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11x^2-610x-2390=0
a = 11; b = -610; c = -2390;
Δ = b2-4ac
Δ = -6102-4·11·(-2390)
Δ = 477260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{477260}=\sqrt{196*2435}=\sqrt{196}*\sqrt{2435}=14\sqrt{2435}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-610)-14\sqrt{2435}}{2*11}=\frac{610-14\sqrt{2435}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-610)+14\sqrt{2435}}{2*11}=\frac{610+14\sqrt{2435}}{22} $
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